You are given a string with words and numbers separated by whitespaces (one space). The words contains only letters. You should check if the string contains three words in succession. For example, the string "start 5 one two three 7 end" contains three words in succession.
Input : String Output : Boolean
This is what I'm trying to do, please point out my mistake. Thanks.
function threeWords(text){
let lst = text.split(' ');
for (let i=0; i< 3; i++) {
if (typeof lst[i] === 'string' && Number(lst[i]) === NaN) {return true}
else {return false;}}
}
If you'd rather continue with your code than use regex, here are your issues:
Here is the fixed code:
function threeWords(text) {
let lst = text.split(' ');
let num_words = 0;
for (let i = 0; i < lst.length; i++) {
if (isNaN(Number(lst[i])))
num_words++
else
num_words = 0
if (num_words === 3)
return true
}
return false;
}Might be easier with a regular expression:
const result = /([A-Za-z]+( |$)){3}/.test('start 5 one two three 7 end');
console.log(result);