I have this code, which does not work if vID=0 because ajax.done does is not a function:
if (vID > 0) {
var ajax = CallPHP('GET', 'grid_main.php', "idquery=7&trkbid=" + vID);
} else {
// Here I need a fake ajax so that the following code will work
var ajax=new Promise();
};
ajax.done(function(data, textStatus, jqXHR) {
// do something
}
how can I fix it? Thank you
More logical is make a function and call that.
function nextStep(data, textStatus, jqXHR) {
// do something
}
if (vID > 0) {
var ajax = CallPHP('GET', 'grid_main.php', "idquery=7&trkbid=" + vID).done(nextStep);
} else {
nextStep({});
};
You can not use a promise since jQuery's Ajax object is not a promise. It would have to look something like
var ajax = {
done: function(method) {
method({});
}
};
ajax.done(function(data, textStatus, jqXHR) {
console.log(data);
});You could use jQuery's deferred
var ajax = $.Deferred().resolve({});
ajax.done(function(data, textStatus, jqXHR) {
console.log(data);
});<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>