How can i sort and rearrange an array that looks like this
fields = [
{
uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
field: new ObjectId("627f816d8443318c6aaa1220"
},
{
uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
field: new ObjectId("6283cb3ca573a56e11587c46"),
}
]
to match the arrangement of this array:
order = [ '6283cb3ca573a56e11587c46', '627f816d8443318c6aaa1220' ]
Here is the output I’m looking for:
[
{
uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
field: new ObjectId("6283cb3ca573a56e11587c46"),
},
{
uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
field: new ObjectId("627f816d8443318c6aaa1220"),
}
]
findIndex and sort but I am very confused
fields.sort((a: any, b: any) => order.indexOf(a.field) - order.indexOf(b.field)) // It does not work
You need to use sort method on the array. And then compare the index of field on the order array.
const data = [
{
uid: '2aa60f96-135b-e179-2b46-516c87a877cc',
field: "6283cb3ca573a56e11587c46",
value: 'test val 6'
},
{
uid: '2c2162cc-37d0-f1e3-96c2-6d9ccb50f38d',
field: "627f816d8443318c6aaa1220",
value: ''
}
]
const order = [ '6283cb3ca573a56e11587c46', '627f816d8443318c6aaa1220' ];
data.sort((a,b) => order.indexOf(a.field) - order.indexOf(b.field));
console.log(data);Notice: ObjectId class is not defined here, so I changed it to string here for simplicity.