This may be a duplicate question. But I didn't find any similar questions in this forum.
I'm trying to modify values in an array to different format.
arrayInput = ['A', 'B', 'C', 'D', 'E', 'F'];
arrayOutput= ['A;B', 'C;D', 'E;F'];
I got the solution with the following approach
let arrayInput = ['A', 'B', 'C', 'D', 'E', 'F']
arrayOutput = [arrayInput[0]+';'+ arrayInput[1], arrayInput[2]+';'+ arrayInput[3]];
if (arrayInput[4]) {
let val = arrayInput[4] + (arrayInput[5] ? ';'+arrayInput[5] : '');
arrayOutput.push(val);
}
console.log(arrayOutput);But I am looking for a generic solution such that even if I have more items in array, it should generate the output in desired format.
['A', 'B', 'C', 'D', 'E', 'F', 'G'] ==> ['A;B', 'C;D', 'E;F', 'G']
['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H'] ==> ['A;B', 'C;D', 'E;F', 'G;H']
Thanks for the support
Use a for loop, and increment it by 2 every iteration:
const arrayInput = ['A', 'B', 'C', 'D', 'E', 'F', 'G'];
const res = [];
for (let i = 0; i < arrayInput.length; i += 2) {
const part1 = arrayInput[i];
const part2 = arrayInput[i + 1];
if (part1) {
res.push(part1 + (part2 ? (';' + part2) : ''));
}
}
console.log(res);You can use Array#reduce as in the following demo. Just in case there's an odd number of elements, I have included a test here ${arr[i+1] ? ";" + arr[i+1] : ""}; otherwise use ${arr[i+1]}, if you always have an even number of elements.
const arrayInput = ['A', 'B', 'C', 'D', 'E', 'F'],
arrayOutput = arrayInput.reduce(
(acc,cur,i,arr) =>
i % 2 === 0 ?
[...acc,`${cur}${arr[i+1] ? ";" + arr[i+1] : ""}`] :
acc,
[]
);
console.log( arrayOutput );
//OUTPUT: ['A;B', 'C;D', 'E;F'];You can try something like this (implementation based on array reduce and join):
const arrayInput = ['A', 'B', 'C', 'D', 'E', 'F'];
let temp = [];
const output = arrayInput.reduce((accumulator, item) => {
if (temp.length < 2) {
temp.push(item);
} else {
accumulator.push(temp.join(';'));
temp = [];
}
return accumulator;
}, []);
console.log(output)