Description:
I want to only return if all the objects in the array match the condition. Now, it's returning the object if at least one condition matches in the array of objects.
If you guys have any more queries regarding this question. I will answer please ask!
Input:
[
{
"_id":"4",
"intends":[
{
"_id":"1",
"status":"Packed"
},
{
"_id":"2",
"status":"Packed"
}
]
},
{
"_id":"5",
"intends":[
{
"_id":"3",
"status":"Packed"
},
{
"_id":"4",
"status":"Created"
}
]
}
]
Current Output:
[
{
"_id":"4",
"intends":[
{
"_id":"1",
"status":"Packed"
},
{
"_id":"2",
"status":"Packed"
}
]
},
{
"_id":"5",
"intends":[
{
"_id":"3",
"status":"Packed"
},
{
"_id":"4",
"status":"Created"
}
]
}
]
Expected Output:
[
{
"_id":"4",
"intends":[
{
"_id":"1",
"status":"Packed"
},
{
"_id":"2",
"status":"Packed"
}
]
}
]
I have tried:
db.collection.find({intends.status: "Packed"})
db.collection.find({intends: {$elemMatch: {status: "Packed"}}})
A possible solution using $elemMatch, $nin and $not.
The $elemMatch, $nin part will give all elements where there is at least one element with status not "Packed". So the $not will reverse it and give elements where every status is "Packed"
db.collection.find({
intends: {
"$not": {
"$elemMatch": {
status: {
"$nin": [
"Packed"
]
}
}
}
}
})
UPDATE
Since here just checking 1 value use $ne instead of $nin
db.collection.find({
intends: {
$not: {
$elemMatch: {
status: {
$ne: "Packed"
}
}
}
}
})
using aggregation $redact and $allElementsTrue
test it at mongoPlayground
db.collection.aggregate([
{
"$redact": {
"$cond": [
{
"$allElementsTrue": {
"$map": {
"input": "$intends",
"as": "intend",
"in": {
"$eq": [
"$$intend.status",
"Packed"
]
}
}
}
},
"$$KEEP",
"$$PRUNE"
]
}
}
])