async function setTime() {
await new Promise(resolve => setTimeout(()=>{console.log("my func is fine")}, 5000));
}
async function realFunction() {
await setTime();
console.log("second call!");
}
In the above code, when i call realFunction, it logs my func is fine, but it does not log second call. Can someone help me understand what am I doing wrong, and how can I get the statement to be logged?
Because you never resolver your promise. You always need to resolve or reject it.
Also async / await is pretty much useless for setTime
function setTime(ms) {
return new Promise((resolve) => setTimeout(resolve, ms))
}
async function realFunction() {
await setTime(5000);
console.log("second call!");
}
The prolbem is that you never resolve the Promise so it's pending forever.
Try to change it like this:
async function setTime() {
await new Promise((resolve) =>
setTimeout(() => {
console.log('my func is fine');
resolve();
}, 5000)
);
}
async function realFunction() {
await setTime();
console.log('second call!');
}
You need to resolve the promise, and for that you can call resolve()
So your setTime() function would look like this:
async function setTime() {
await new Promise(resolve => setTimeout(()=>{
console.log("my func is fine")
return resolve();
}, 5000));
}