I'm trying to code a function into my card game to check if the first 2 cards hold any 2 out of the following 3 values: 6, 7 or 8
i.e. 6&7, 7&8, or 6&8.
For the sake of being specific: I don't want it to return true if its 2 of the same value but I imagine that could be done with a && card1Value!==card2Value added onto the conditions of the logical statement.
From there I'll then need to make it so that card3Value is checked for the missing value.
I'd personally split that up a little:
function threeCardsAreValid(card1, card2, card3) {
if(!twoCardsAreValid(card1, card2)) return false
if (cardIs6Or7Or8(card3) && card3 !== card1 && card3!== card2) return true
return false
}
function twoCardsAreValid(card1, card2) {
if (cardIs6Or7Or8(card1) && cardIs6Or7Or8(card2) && card1 !== card2) {
return true
}
return false
}
function cardIs6Or7Or8(card) {
return (card === 6 | card === 7 | card === 8)
}
What I would personnaly go for is filtering the array and creating a set to see if there are no duplicates.
Then, if the result array has a length greater than 2, then at least 2 of the 3 cards are valid.
function checkHand(card1, card2, card3){
const arr = [card1,card3,card2]
const validHands = [6,7,8]
const validHandsFilteredWithoutDuplicates = [...new Set(arr.filter(x => validHands.includes(x)))]
return validHandsFilteredWithoutDuplicates.length >= 2
}
console.log(checkHand(6,7,9)) // true
console.log(checkHand(1,2,3)) // false
console.log(checkHand(7,7,4)) // false
console.log(checkHand(6,7,8)) // true