I have this array (java script array of objects)
users=[{name:'arrow',age:50,id:444}
{name:'bow',age:66,id:884}
{name:'arrow',age:30,id:99},
{name:'apple',age:50,id:999}
{name:'bow',age:50,id:9669}]
I want to remove second occurrence of same name , in this case , I want to remove {name:'arrow',age:30,id:99} and {name:'bow',age:50,id:9669} and retain first occurrences{name:'arrow',age:50,id:444} and {name:'bow',age:66,id:884}
Resulting array should be :
users= [{name:'arrow',age:50,id:444}
{name:'bow',age:66,id:884},
{name:'apple',age:50,id:999}]
const users = [
{ name: 'arrow', age: 50, id: 444 },
{ name: 'bow', age: 66, id: 884 },
{ name: 'arrow', age: 30, id: 99 },
{ name: 'apple', age: 50, id: 999 },
{ name: 'bow', age: 50, id: 9669 }
]
const uniqueUsers = users.reduce((acc, user) => {
if (!acc.find(u => u.name === user.name)) {
acc.push(user)
}
return acc
}, [])
I'd go with the approach of array.filter:
function removeDuplicateKeyFromArray(arrayOfObjects,keyName){
keyHolder = {}
arrayOfObjects.filter((obj)=>{
if(keyHolder[obj.keyName]){
return false
}
keyHolder[obj.keyName] = 1 //or true
return true
})
}
I would create 2 for-loops, to filter out any duplicates. here's my code:
let users = [{name:'arrow',age:50,id:444},
{name:'bow',age:66,id:884},
{name:'arrow',age:30,id:99},
{name:'apple',age: 50,id: 990},
{name:'bow',age: 50,id: 9669}]
for (let i = 0; i < users.length; i++) {
for(let x = 0; i < users.length; i++) {
if(users[i].name == users[x].name) {
users.splice(users[x], 1)
}
}
}