public class test {
public static void main(String[] args) {
String[] arr = {"0 1.2.3.4","a b.c.d.e"};
System.out.println(arr[0].split(".")[2]);
}
}
I am using java 8.
the expected output is 3.
The argument to split is a regular expression, not a literal 'this is the string you should scan for'. The . symbol in regex means 'anything', so it's like " ".split(" ") - the string you're passing is all separators, hence, you get no output.
.split(Pattern.quote(".")) will take care of it.
EDIT: To go in some detail - given that the string consists of all separators, split initially provides you with an array filled with empty strings; one for each position 'in between' any character (as each character is a separator). However, by default split will strip all empty strings off of the end, hence you end up with a 0-length string array.