Empresas
Empregos
  • Sobre nós
  • Soluções
    • Publicação de vagas
      Publique sua vaga e receba candidatos qualificados em 48h.
    • Avaliações de candidatos
      Mais de 500 testes técnicos e psicológicos, mais anti-fraude.
    • Headhunting
      Busca executiva personalizada do início ao fim.
    • Folha de Pagamento + EOR
      Dispersão de folha e EOR em mais de 15 países da LATAM.
  • Preços
  • Empregos

0

260
Visualizações
Rounding to 5 cents - better approach

The total price should be rounded to 5 cents according to following rules.

  1. If number ends with 0.01 to 0.04 cents, round number down, e.g. 15.52 to 15.50
  2. If number ends with 0.06 to 0.09 cents, round up, e.g. 15.57 to 15.60
  3. If number is less than 5 cents then number price is 5 cents, e.g. 0.04 to 0.05
  4. If number ends with 0 or 5 cents then don't round.

I have come up with following approach but seems to heavy and wonder if someone has a better idea?

var divisionValue = 0.05;

if (number > 0 && number < divisionValue) {
    return divisionValue;
}

var roundedNumber = number;

var division = roundedNumber / divisionValue;
var divisionFormatted = +(division).toFixed(2);

var moduloRemainder = divisionFormatted % 1;
var divisionRemainderFormatted = +(moduloRemainder).toFixed(2);

// When there is no remainder, the value ends with 0.05 or 0.1
if (divisionRemainderFormatted === 0) {
    return roundedNumber;
} else if (divisionRemainderFormatted !== 0) {
    var diff = divisionFormatted - divisionRemainderFormatted;
    if (diff % 2) {
        // For values ending with 0.06 to 0.09 round up
        roundedNumber = Math.ceil(number * 10) / 10;
    } else {
        // For values ending with 0.01 to 0.04 round up
        roundedNumber = Math.floor(number * 10) / 10;
    }
}

return +(roundedNumber).toFixed(2

Test

it('Slovak rounding to 5 eurocents', function () {
    // not round
    expect(MathService.roundToFiveEurocent(23)).toBe(23);
    expect(MathService.roundToFiveEurocent(23.1)).toBe(23.10);
    expect(MathService.roundToFiveEurocent(23.15)).toBe(23.15);

    // round down
    expect(MathService.roundToFiveEurocent(23.11)).toBe(23.10);
    expect(MathService.roundToFiveEurocent(23.12)).toBe(23.10);
    expect(MathService.roundToFiveEurocent(23.13)).toBe(23.10);
    expect(MathService.roundToFiveEurocent(23.14)).toBe(23.10);

    // round up
    expect(MathService.roundToFiveEurocent(23.17)).toBe(23.20);
    expect(MathService.roundToFiveEurocent(23.18)).toBe(23.20);
    expect(MathService.roundToFiveEurocent(23.19)).toBe(23.20);

    // round to 0.05
    expect(MathService.roundToFiveEurocent(0.01)).toBe(0.05);
    expect(MathService.roundToFiveEurocent(0.02)).toBe(0.05);
    expect(MathService.roundToFiveEurocent(0.03)).toBe(0.05);
    expect(MathService.roundToFiveEurocent(0.04)).toBe(0.05);
});
about 4 years ago · Juan Pablo Isaza
2 Respostas
Responde à pergunta

0

So basically you need to play with adding 0.05 and defining your exceptions

// not round
values = [
  [23, 23],
  [23.1, 23.10],
  [23.15, 23.15],

  // round down
  [23.11, 23.10],
  [23.12, 23.10],
  [23.13, 23.10],
  [23.14, 23.10],

  // round up
  [23.17, 23.20],
  [23.18, 23.20],
  [23.19, 23.20],

  // round to 0.05
  [0.01, 0.05],
  [0.02, 0.05],
  [0.03, 0.05],
  [0.04, 0.05]
]

function test_round(val) {
  to_round = parseFloat(val).toFixed(2)
  if (to_round < 0.05)
    return 0.05

  ref = to_round * 10
  if (ref - parseInt(ref) == 0.5)
    return to_round

  temp = parseFloat(to_round) + 0.05;
  clean = parseFloat(parseInt(temp * 10) / 10)
  return clean
}

function test(_vals) {
  for (v of _vals) {
    if (v[1] != test_round(v[0])) {
      console.log(['Failed rounding', '-', v, '-', test_round(v[0])].join(' '))
    }
  }
}

test(values)

about 4 years ago · Juan Pablo Isaza Relatório

0

Here's a one liner...

function rt5( x ) {return x < 0 ? null : 0 < x && x < 0.05 ? 0.05 : x * 20 % 1 === 0 ? x : Math.floor( ( x + 0.05 ) / 0.1 ) * 2 / 20 }

console.log( `rt5( 0.02 ) = ${rt5(0.02)}` ); 
console.log( `rt5( 0.14 ) = ${rt5(0.14)}` ); 
console.log( `rt5( 0.15 ) = ${rt5(0.15)}` ); 
console.log( `rt5( 0.16 ) = ${rt5(0.16)}` );

console.log( `rt5( 999999999999.94 ) = ${rt5(999999999999.94)}` );
console.log( `rt5( 999999999999.95 ) = ${rt5(999999999999.95)}` );
console.log( `rt5( 999999999999.96 ) = ${rt5(999999999999.96)}` );

console.log( `rt5( -1.05 ) = ${rt5(-1.05)}` );

about 4 years ago · Juan Pablo Isaza Relatório
Responde à pergunta
Encontrar trabalhos remotos

Descubra a nova forma de encontrar um emprego!

melhores empregos
Principais categorias de trabalho
Empresas
Postar vaga Preços Comercial
Jurídico
Termos e Condições Política de privacidade
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Recomende algumas ofertas para mim
Preciso de ajuda