I want to filter my result in javascript.
const ids =["2", "3"];
const data =
[
{"id":'1', 'name:'alex' , 'subject':'english' },
{"id":'2', 'name:'alex' , 'subject':'english' },
{"id":'3', 'name:'alex' , 'subject':'english' },
{"id":'4', 'name:'alex' , 'subject':'english' },
]
I want to filter data and remove those id's found in ids. This is what I have tried so far
const NewData = ids.reduce(function (key, index) {
return (data.filter(x => x.id !== key))
})
But it returns
[
{"id":'1', 'name:'alex' , 'subject':'english' },
{"id":'3', 'name:'alex' , 'subject':'english' },
{"id":'4', 'name:'alex' , 'subject':'english' },
]
I want to remove id 2 & '3' from data but it only remove id 2.Hope You understand my issue.
No need to use reduce. A simple filter will work.
Example:
const ids = ["2", "3"];
const data = [
{ id: "1", name: "alex", subject: "english" },
{ id: "2", name: "alex", subject: "english" },
{ id: "3", name: "alex", subject: "english" },
{ id: "4", name: "alex", subject: "english" },
];
const new_data = data.filter((x) => ids.includes(x.id));
console.log(new_data);If the type of id in the original array differs from the type of id in the data, you can use .map(a=>parseInt(a)) and then check with .includes()
const ids = ["2", "3"];
const data = [
{ id: 1, name: "alex", subject: "english" },
{ id: 2, name: "alex", subject: "english" },
{ id: 3, name: "alex", subject: "english" },
{ id: 4, name: "alex", subject: "english" },
];
const ids_int = ids.map(a => parseInt(a))
const filtered = data.filter(x => !ids_int.includes(x.id))
console.log(filtered)