i do not understood, how this code working after if(y in hash) most complicated for me is hash is empty and i do not push any value in hash so what will happened behind the scene and y in hash what its meaning?
var twoSum = function(nums, target) {
const hash = {}
// console.log(hash)
for (const i in nums) {
const x = nums[i];
const y = target - x
// console.log(y)
if (y in hash)
return [i, hash[y]]
hash[x] = i
}
}
let arr = [2, 3, 4, 5, 6]
console.log(twoSum(arr, 11))hash is empty and I do not push any value
hash[x] = i part add values to hash, because it is out of if(y in hash) condition
y in hashwhat it's meaning?
As Nick Parsons mentioned in a comment "it's checking if the key stored in y is a key in the hash object (or its prototype chain)"