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VisualizaçõesHow to reverse the order of svg elements
I am working with a svg element which is following
<svg class="layer1" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 150 150">
<rect class="bg" id="bg" width="150" height="150" fill="#e6e6e6"></rect>
<circle class="circ0" id="circ0" cx="75" cy="75" r="72" fill="none" stroke="blue" stroke-linecap="round" stroke-linejoin="round"></circle>
<circle class="circ1" id="circ1" cx="75" cy="75" r="69" fill="none" stroke="green" stroke-linecap="round" stroke-linejoin="round"></circle>
<circle class="circ2" id="circ2" cx="75" cy="75" r="66" fill="none" stroke="red" stroke-linecap="round" stroke-linejoin="round"></circle>
<script href="index.js"></script>
</svg>I want to reverse the order of these circles with javascript, which I am currently doing by this way
const svg = document.querySelector("svg");
var x = document.querySelectorAll("[class^='circ']");
var bucket = [];
x.forEach((a, i) => {
bucket.push(a)
});
bucket.reverse();
x.forEach(
(a, i) => a.parentNode.removeChild(a)
);
bucket.forEach(
(a, i) => {
a.setAttribute("class", 'circ' + [i]);
a.setAttribute("id", "circ" + [i]);
svg.appendChild(a);
}
)<svg class="layer1" xmlns="http://www.w3.org/2000/svg" viewBox="0 0 150 150">
<rect class="bg" id="bg" width="150" height="150" fill="#e6e6e6"></rect>
<circle class="circ0" id="circ0" cx="75" cy="75" r="72" fill="none" stroke="blue" stroke-linecap="round" stroke-linejoin="round"></circle>
<circle class="circ1" id="circ1" cx="75" cy="75" r="69" fill="none" stroke="green" stroke-linecap="round" stroke-linejoin="round"></circle>
<circle class="circ2" id="circ2" cx="75" cy="75" r="66" fill="none" stroke="red" stroke-linecap="round" stroke-linejoin="round"></circle>
<script href="index.js"></script>
</svg>It gives me this
Is there a better way of doing this?
·
Juan Pablo Isaza
1 Respostas
Responde à pergunta0
append(child) by itself moves DOM Nodes. So your code can be simplified.
But for complexer SVG you probably want to swap DOM positions, because there could be other Elements in between you don't want to affect.
- Hold CTRL key to see what happens with
append - Click to see the swapping version,
a matter of processing an Array and swapping the first with the last element. - Note:
appendwas not available in Internet Explorer, that is why you see most posts usingappendChild.
Modern browsers have loads more DOM goodies:replaceWithafter,beforeetc.
<svg viewBox="0 0 10 10" style="height:200px">
<style>
text { font-size: 2px }
[y="3"]{ fill:yellow }
.first { stroke: black; stroke-width: 0.5 }
</style>
<rect class="bg" id="bg" width="10" height="10" fill="grey"></rect>
<circle class="first" id="c0" cx="2" cy="5" r="2" fill="red" />
<text x="0" y="3">R</text>
<circle class="second" id="c1" cx="4" cy="5" r="3" fill="green" />
<text x="1" y="3">G</text>
<circle class="last" id="c2" cx="6" cy="5" r="4" fill="blue" />
<text x="2" y="3">B</text>
<text x="1" y="6">Click Me!</text>
</svg>
<script>
let svg = document.querySelector("svg");
function append() {
[...svg.querySelectorAll("circle")]
.reverse().forEach((c, i) => {
c.parentNode.append(c);
c.setAttribute("class", c.id = 'c' + i);
});
}
function swap() {
function swapElements(e1, e2) {
let {id,previousSibling,className:{baseVal:c2}} = e2;
e1.after(e2); // put e2 after e1
e2.id = e1.id; e2.setAttribute("class", e1.getAttribute("class"));
previousSibling.after(e1); // put e1 after where e2 WAS
e1.id = id; e1.setAttribute("class", c2);
}
let circles = [...svg.querySelectorAll("circle")];
while (circles.length) {
let c1 = circles.shift();
if (circles.length) swapElements(c1, circles.pop())
}
}
svg.onclick = (e) => (e.ctrlKey && append()) || swap();
</script>
·
Juan Pablo Isaza
Relatório
Responde à pergunta