Question

0

163

Visualizações

String tokenizer method

Consider strings with this format:

id-string1-string2-string3.extension

where id, string1, string2 and string3 can be string of variable length, and extension is an image extension type.

For example, two possible strings could be:

Il2dK-Ud2d9-Kod2d-d9dwo.jpg

j54fwf3da-7jrg-9eujodww-kio98ujk.png

I need tokenizer method in JavaScript for an express/nodejs API that takes these strings in input and outputs an object with this format:

{a: id-string1-string2, b: string3, c: extension}

For the example strings this tokenizer should then output:

{a: Il2dK-Ud2d9-Kod2d, b: d9dwo, c: jpg}

{a: j54fwf3da-7jrg-9eujodww, b: kio98ujk, c: png}

I think this can be done with regex. I tried to use the following regex match(/[^-]+/g), but this tokenize every substring, I need a way to skip the first 2 char "-" but couldn't find it out.

Do you have any ideas? Or could you provide me a better solution instead of using regex? Thanks very much!

about 4 years ago · Juan Pablo Isaza

3 Respostas

Responde à pergunta

0

Responde à pergunta

Encontrar trabalhos remotos

Answer 1 · 2022-07-03T00:16:32.851Z

You might use a pattern with capture groups:

^(?<a>[^\s-]+(?:-[^\s-]+)*)-(?<b>[^\s.-]+)\.(?<c>\w+)$

Explanation

^ Start of string
(?<a>[^\s-]+(?:-[^\s-]+)*) Named group a, match any char except a whitespace char or - and optionally repeat - and again any char except a whitespace char
- Match literally
(?<b>[^\s.-]+) Named group b, match 1+ chars other than . - or a whitespace char
\. Match .
(?<c>\w+) Named group c, match 1+ word chars for the extension
$ End of string

regex demo

const regex = /^(?<a>[^\s-]+(?:-[^\s-]+)*)-(?<b>[^\s.-]+)\.(?<c>\w+)$/;
[
  "id-string1-string2-string3.extension",
  "Il2dK-Ud2d9-Kod2d-d9dwo.jpg",
  "j54fwf3da-7jrg-9eujodww-kio98ujk.png",
  "a-b-c",
  "a.b"
].forEach(s => {
  const m = s.match(regex);
  if (m) {
    console.log(m.groups);
  }
});

Without named groups, you can use capture groups and create the objects:

const regex = /^([^\s-]+(?:-[^\s-]+)*)-([^\s.-]+)\.(\w+)$/;
[
  "id-string1-string2-string3.extension",
  "Il2dK-Ud2d9-Kod2d-d9dwo.jpg",
  "j54fwf3da-7jrg-9eujodww-kio98ujk.png",
  "a-b-c",
  "a.b"
].forEach(s => {
  const m = s.match(regex);
  if (m) {
    console.log({
      "a": m[1],
      "b": m[2],
      "c": m[3]
    });
  }
});

Answer 2 · 2022-07-03T00:16:32.861Z

You can achieve this using spit as:

const str = 'Il2dK-Ud2d9-Kod2d-d9dwo.jpg';
const [restStr, c] = str.split('.');
const [a, b] = restStr.split(/-([a-z0-9]+$)/);
const result = { a, b, c };
console.log(result);

Answer 3 · 2022-07-03T00:16:32.868Z

To split at the last hyphen or any period:

res = str.split(/-(?![^-]*-)|\./);

See this demo at regex101 or JS demo at tio.run

At the position after any hyphen a negative lookahead (zero-length assertion/condtion) checks if there is not another hyphen ahead with any amount of non-hyphens in between OR match period.

0

163

String tokenizer method

3 Respostas

0

0

0

Encontrar trabalhos remotos

Andres GPT