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Links not changed after alphabetically sorting

I have a list that is sorted alphabetically, but links from each li are not changing if I verify the elements links after sorting. Can't figure out what am I missing.

Any help with explanations would be greatly appreciated.

My code in HTML:

<ul class="row list-unstyled" id="testingList">
  <li class="col-sm-6 col-lg-4 col-xl-3 mb-3 top-box"><a class="top-box__content" href="https://www.example.com/info/1" target="_blank">
      <div class="row no-gutters">
        <div class="col">
          <h3 class="top-box__title">Pink</h3>
        </div>
      </div>
    </a>
  </li>
  <li class="col-sm-6 col-lg-4 col-xl-3 mb-3 top-box"><a class="top-box__content" href="https://www.example.com/info/2" target="_blank">
      <div class="row no-gutters">
        <div class="col">
          <h3 class="top-box__title">White</h3>
        </div>
      </div>
    </a>
  </li>
  <li class="col-sm-6 col-lg-4 col-xl-3 mb-3 top-box"><a class="top-box__content" href="https://www.example.com/info/3" target="_blank">
      <div class="row no-gutters">
        <div class="col">
          <h3 class="top-box__title">Brown</h3>
        </div>
      </div>
    </a>
  </li>
</ul>

My JS code:

let pickList = document.querySelector("#testingList");

let li = pickList.querySelectorAll("a");

resultList = [];

for (let i = 0; i < li.length; i++) {
  resultList.push(li[i].innerHTML);
  console.log(resultList);
}

resultList.sort();

for (let j = 0; j < li.length; j++) {
  li[j].innerHTML = resultList[j];
}

about 4 years ago · Juan Pablo Isaza
1 Respostas
Responde à pergunta

0

You are rewriting the innerHTML of the <a> elements, but not changing their .href attributes. It might be simpler to just move the elements around instead of rebuilding them.

let pickList = document.querySelector("#testingList");

let lis = [...pickList.querySelectorAll("li")];

lis.sort((a, b) => {
  // sort on the text of the h3 elements contained within
  const asort = a.querySelector('h3.top-box__title').innerText;
  const bsort = b.querySelector('h3.top-box__title').innerText;
  return asort.localeCompare(bsort);
});

// append each li to the list in order
lis.forEach(li => pickList.appendChild(li));
<ul class="row list-unstyled" id="testingList">
  <li class="col-sm-6 col-lg-4 col-xl-3 mb-3 top-box"><a class="top-box__content" href="https://www.example.com/info/1" target="_blank">
      <div class="row no-gutters">
        <div class="col">
          <h3 class="top-box__title">Pink</h3>
        </div>
      </div>
    </a>
  </li>
  <li class="col-sm-6 col-lg-4 col-xl-3 mb-3 top-box"><a class="top-box__content" href="https://www.example.com/info/2" target="_blank">
      <div class="row no-gutters">
        <div class="col">
          <h3 class="top-box__title">White</h3>
        </div>
      </div>
    </a>
  </li>
  <li class="col-sm-6 col-lg-4 col-xl-3 mb-3 top-box"><a class="top-box__content" href="https://www.example.com/info/3" target="_blank">
      <div class="row no-gutters">
        <div class="col">
          <h3 class="top-box__title">Brown</h3>
        </div>
      </div>
    </a>
  </li>
</ul>

about 4 years ago · Juan Pablo Isaza Relatório
Responde à pergunta
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