I have an array given below, every element of this array consists of another array.
var array = [
['201', 'Tom', 'EES', 'California'],
['189', 'Charlie', 'EE', 'New Jersey'],
['245', 'Lisa', 'EEF', 'New Jersey'],
['743', 'Niall', 'EEC', 'Chicago'],
['653', 'Tim', 'EES', 'Miami'],
['333', 'Dev', 'EE', 'Washington'],
['333', 'Rhonda', 'EEC', 'Washington']
]
I want it to be sorted on the basis of 3rd value and in this order [EE,EES,EEC,EEF].
array should be:
[
['189', 'Charlie', 'EE', 'New Jersey'],
['333', 'Dev', 'EE', 'Washington'],
['201', 'Tom', 'EES', 'California'],
['653', 'Tim', 'EES', 'Miami'],
['743', 'Niall', 'EEC', 'Chicago'],
['333', 'Rhonda', 'EEC', 'Washington'],
['245', 'Lisa', 'EEF', 'New Jersey']
]
Note :- Original array will be having n no of elements, all i want is that first EE elements should come , then EES, EEC and then EEF
Thanks in advance.
//this is my code! You can use array.sort(...) to do this
var array=[['201','Tom','EES','California'],['189','Charlie','EE','New Jersey'],
['245','Lisa','EEF','New Jersey'],['743','Niall','EEC','Chicago'],['653','Tim','EES','Miami'],
['333','Dev','EE','Washington'],['333','Rhonda','EEC','Washington']];
let _result = array.sort(
function(a, b){
if (a[2].toLowerCase() < b[2].toLowerCase()) return -1;
if (a[2].toLowerCase() > b[2].toLowerCase()) return 1;
return 0;
}
)
console.log(_result);