I have a two sets of elements, one holds list of numbers and second of names. something like this.
A: 4,
B: 3,
C: 2,
A: 5,
C: 3,
And my task is to find elements with smallest value and highest value.
I know that i could create array of objects and sort it with map [{A: 4},{C:2}....]
But i was wondering is there any efficient ways of doing it.
Instead of creating a have object, and use three loops.
Would it be possible to replace it with something more efficient.
Like set or something where i could just call set.getItemWithMinValue, set.getItemWithMaxValue
and return would be : C:2, A:5
Sorry for silly quesition, i am still learning.
This would be one way of doing it. Caution: the array will be changed (sorted) in the course of the script.
const arr=[{A: 4},{B: 3},{C: 2},{A: 5},{C: 3}],
val=o=>Object.values(o)[0];
arr.sort((a,b)=>val(a)-val(b));
console.log(arr[0],arr[arr.length-1])You are going to have to loop, parse the object into its values, and check if the value is greater or less.
var data = [
{ A: 4 },
{ B: 3 },
{ C: 2 },
{ A: 5 },
{ C: 3 },
];
const results = data.reduce((minMax, item) => {
const value = Object.values(item)[0];
if (!minMax) {
minMax = {
min: { value, item },
max: { value, item },
}
} else if (minMax.min.value > value) {
minMax.min = { value, item };
} else if (minMax.max.value < value) {
minMax.max = { value, item };
}
return minMax;
}, null);
console.log(results.min.item);
console.log(results.max.item);You could take a single loop with getting the entries from the object.
This approach expects only a singl min and max value.
const
array = [{ A: 4 }, { B: 3 }, { C: 2 }, { A: 5 }, { C: 3 }];
let min, max;
for (const object of array) {
const [[k, v]] = Object.entries(object);
if (!min || min[1] > v) min = [k, v];
if (!max || max[1] < v) max = [k, v];
}
console.log('min', Object.fromEntries([min]));
console.log('max', Object.fromEntries([max]));This approach respects more than one name with same min or max value.
const
array = [{ A: 4 }, { B: 3 }, { C: 2 }, { A: 5 }, { C: 3 }, { F: 2 }];
let min, max;
for (const object of array) {
const v = Object.values(object)[0];
if (!min || min[1] > v) min = [[object], v];
else if (min[1] === v) min[0].push(object);
if (!max || max[1] < v) max = [[object], v];
else if (max[1] === v) max[0].push(object);
}
console.log('min', min[0]);
console.log('max', max[0]);