Using optional chaining with function calls causes the expression to automatically return undefined instead of throwing an exception if the method isn't found.

Note: The code is using spread syntax, not rest parameters.

const fn1 = undefined
const args = []
const fn2 = () => {}
const fn3 = () => {}

console.log(fn1?.(...args, fn2, fn3))

Error:

console.log(fn1?.(...args, fn2, fn3))
                                ^
TypeError: Function.prototype.apply was called on undefined, which is an undefined and not a function