Just use filter as you mention in question for compare if value is > of 0 like:

const array =  [[ 'PENNY', 0 ],[ 'NICKEL', 0 ],[ 'DIME', 20 ],[ 'QUARTER', 50 ]];
console.log(array.filter(el => el[1] > 0));

Reference:

• Array.prototype.filter()

Filter by the second element:

const array = [[ 'PENNY', 0 ],[ 'NICKEL', 0 ],[ 'DIME', 20 ],[ 'QUARTER', 50 ]];

const filtered = array.filter(([, count]) => count > 0);

console.log(filtered);

[, count] is destructuring, which you can read about in full here

const array = [[ 'PENNY', 0 ],[ 'NICKEL', 0 ],[ 'DIME', 20 ],[ 'QUARTER', 50 ]]
 
const arrayFiltered = array.filter((item) => item[1] > 0)
console.log(arrayFiltered)

filter() method return a new array based on the rule you specify inside. In this case, we want a new array with item[1] (the index of our array) to be > 0.