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VisualizaçõesHow to use type of in objects to get oddValues
1.Here is the task.
Declare a function removeOddValues.
- @param {object} ??? - an object
- @returns {object} a new object that contains the same key/value pairs as the given object, except that any key/value pair where the value is an ODD number is removed
2.Your code here.
function removeOddValues(obj){
let result = {};
for(const key in obj){
if(typeof obj[key] % 2 === 0){
result[key] = obj[key];
return result;
}
else if(!isNaN(obj[key]))
return obj;
}
}
3.Here is the test.
test(removeOddValues({ a: 1, b: 2, c: 3 }), { b: 2 });
test(removeOddValues({ a: "1", b: "2", c: "3" }), {
a: "1",
b: "2",
c: "3",
});
// If a line gets really long, you can put key/value pairs on new lines.
4.Here is the error.
But output are supposed to be {b:2} and { a: "1", b: "2", c: "3" }, not both are { a: "1", b: "2", c: "3" }
·
Juan Pablo Isaza
2 Respostas
Responde à pergunta0
I think your problem is in the if check. You are checking if the typeof value is divisible by 2, it will return NaN since typeof obj[key] is returning string or number and modulus of that will be NaN. Your condition in else if passes so the whole object is being returned.
·
Juan Pablo Isaza
Relatório
0
Here is a more functional way of doing the same:
function removeOddValues(o){
return Object.entries(o)
.reduce((a,[k,v])=>{
if (typeof v==="string" || v%2===0) a[k]=v;
return a;
}, {});
}
console.log(removeOddValues({ a: 1, b: 2, c: 3 }));
console.log(removeOddValues({ a: "1", b: "2", c: "3" }));
·
Juan Pablo Isaza
Relatório
Responde à pergunta