How can I get all the indexes based on a condition for an array of objects? I have tried the code below, but it's returning only the first occurrence.
a = [
{prop1:"abc",prop2:"yutu"},
{prop1:"bnmb",prop2:"yutu"},
{prop1:"zxvz",prop2:"qwrq"}];
index = a.findIndex(x => x.prop2 ==="yutu");
console.log(index);findIndex will return only one matching index, You can check value against property prop2 using filter
a = [
{prop1:"abc",prop2:"yutu"},
{prop1:"bnmb",prop2:"yutu"},
{prop1:"zxvz",prop2:"qwrq"}];
const allIndexes = a
.map((e, i) => e.prop2 === 'yutu' ? i : -1)
.filter(index => index !== -1);
console.log(allIndexes);
// This is one liner solution might not work in older IE ('flatMap')
const notSupportedInIE =a.flatMap((e, i) => e.prop2 === 'yutu' ? i : []);
console.log(notSupportedInIE);Try Array.reduce
a = [
{prop1:"abc",prop2:"yutu"},
{prop1:"bnmb",prop2:"yutu"},
{prop1:"zxvz",prop2:"qwrq"}];
index = a.reduce((acc, {prop2}, index) => prop2 ==="yutu" ? [...acc, index] : acc, []);
console.log(index);You can use normal for loop and when ever the prop2 matches push the index in the array
const a = [{
prop1: "abc",
prop2: "yutu"
},
{
prop1: "bnmb",
prop2: "yutu"
},
{
prop1: "zxvz",
prop2: "qwrq"
}
];
const indArr = [];
for (let i = 0; i < a.length; i++) {
if (a[i].prop2 === 'yutu') {
indArr.push(i)
}
}
console.log(indArr);