Estoy tratando de escribir una función que calcule la edad promedio de los estudiantes en una lista de objetos de estudiantes, pero cuando ejecuto el código, la función imprime NaN como salida
function average_age(){ let total = 0; students.forEach(s => { total += Number(s.age); }); return total/size } console.log("Average age is : " + average_age())así es como construí la matriz (obtuve la entrada del usuario)
const size = 5 let students = [size] for (let i=1; i<=5; i++){ let name = prompt("Enter student's name: ") let gender = prompt ("Enter student's gender: ") students.push({ name: name, gender: gender, age:Math.round(Math.random() * (35 - 17 + 1) + 1), grade:Math.round(Math.random() * (100 + 1)) }) } //display student info students.map(s =>{ console.log("Name: " + s.name); console.log("gender: " + s.gender); console.log("age: " + s.age); console.log("grade: " + s.grade); console.log(); })Traté de calcular la edad total de los estudiantes (eliminando la operación de división) para verificar si el problema era la división, pero aún obtuve NaN como salida
Puede verificar 3 enfoques allí para su problema:
const students = [ { id: 1, name: "john", age: 25 }, { id: 2, name: "jack", age: 31 }, { id: 3, name: "joe", age: 26 }, { id: 4, name: "jamal", age: 21 }, ]; // Your approach: function average_age() { let total = 0; let numberOfStudents = students.length; students.map(student => { total += Number(student.age); }); return total / numberOfStudents; } // Second approach: function average_age_second() { let total = 0; let numberOfStudents = students.length; students.forEach(student => { total += Number(student.age); }); return total / numberOfStudents; } // Third approach: function average_age_third() { let numberOfStudents = students.length; const total = students.reduce((partialSum, student) => partialSum + student.age, 0); return total / numberOfStudents; } console.log("Average age is : " + average_age()); console.log("Average age is : " + average_age_second()); console.log("Average age is : " + average_age_third());Suponiendo que la matriz de estudiantes tiene el siguiente formato (después de recopilar las entradas):
let students = [ { name: "aaaa" , gender: "male" , age: 17, grade: 63 }, { name: "bbbb" , gender: "male" , age: 20, grade: 70 }, { name: "yyyy" , gender: "female", age: 18, grade: 45 }, { name: "zzzz" , gender: "female", age: 18, grade: 70 }, { name: "xxxx" , gender: "male" , age: 20, grade: 83 }, ];Una posible solución es la siguiente:
let students = [ { name: "aaaa" , gender: "male" , age: 17, grade: 63 }, { name: "bbbb" , gender: "male" , age: 20, grade: 70 }, { name: "yyyy" , gender: "female", age: 18, grade: 45 }, { name: "zzzz" , gender: "female", age: 18, grade: 70 }, { name: "xxxx" , gender: "male" , age: 20, grade: 83 }, ]; //------------------------------ function average_age(students){ let total = 0; students.forEach(s => total +=s.age); return total/students.length } //------------------------------ console.log("Average age is : " + average_age(students));