I tried:
(no|yes)\w{3,6}
but this basically works, but there is some catch in it. when I say between 3 to 6 characters long, it doesn't count yes or no.
for example: if I have a word yesss, it wont match with it, even though it has only 5 characters. because it starts counting after 'yes'. but it'll match if i have 'yessssss'.
what is the correct regular expression for it?
You can use
const matches = text.match(/\b(?=\w*(?:yes|no))\w{3,6}\b/ig);
Details:
\b - word boundary(?=\w*(?:yes|no)) - after any zero or more word chars, there must be yes or no\w{3,6} - three to six word chars\b - word boundary.See a JavaScript demo:
const text = "abcno and abcyes and abyesno";
const matches = text.match(/\b(?=\w*(?:yes|no))\w{3,6}\b/ig);
console.log(matches);If you only want to match words consisting of letters:
const text = "abcno and abcyes and abyesno";
const matches = text.match(/\b(?=\p{L}*(?:yes|no))\p{L}{3,6}\b/igu);
console.log(matches);The \p{L} matches any Unicode letter and u enables this pattern support in an ECMAScript 2018+ compliant regex engine. If you only work with ASCII letters, replace \p{L} with [a-zA-Z] and remove u flag.