You can do this. Get the array of users.

const users = [{ "name": "John doe", "age": 51 }, { "name": "Jake kim", "age": 50 }, { "name": "Jim son", "age": 51 }]

Get the array of ages

const age = [50,51,52,53,54]

Then you can map through the array of ages, returning an object that has the user that has the same age, here is the algorithm.

const mapped = age.map(age => {
  const user = {}
  user[age] = users.find(ob => ob.age === age);
  return user;
})

If you print out the mapped result. This is what it will look like, For the ages that we couldn't find their users, they just have an undefined value.

    console.log(mapped)
    [
      { '50': { name: 'Jake kim', age: 50 } },
      { '51': { name: 'John doe', age: 51 } },
      { '52': undefined },
      { '53': undefined },
      { '54': undefined }
    ]

I don't think you'll need the age data in your case. However I've provided the both versions which one use the age list but other does not. Please find them below.

const users = [{ "name": "John doe", "age": 51 }, { "name": "Jake kim", "age": 50 }, { "name": "Jim son", "age": 51 }];
const age = [50, 51, 52, 53, 54];

const desired = users.reduce((prev, cur) => {
  (prev[cur.age] ?? (prev[cur.age] = [])).push(cur); 
  return prev;
}, {});

console.log("This is the expected result", desired); 

const desired2 = users.reduce((prev, cur) => {
  (prev[cur.age] ?? (prev[cur.age] = [])).push(cur); 
  return prev;
}, age.reduce((prev, cur) => {
  prev[cur] = [];
  return prev;
}, {}));

console.log("This is the expected result with empty ages", desired2);