I read a post stating how does Javascript gets compiled to machine code

Why does JavaScript get compiled to machine code?

My problem is I have multiple javascript files ending with .js and how can I differentiate machine code also with .js ending and normal .js source code ?

For example, machine code in javascript file ending with .js would look like this

 Copyright FusionCharts Technologies LLP
 License Information at <http://www.fusioncharts.com/license>
 @version 3.12.0
*/
(function(sb,Nb){"object"===typeof module&&module.exports?module.exports=sb.document?Nb(sb):function(N){if(!N.document)throw Error("Window with document not present");return Nb(N,!0)}:sb.FusionCharts=Nb(sb,!0)})("undefined"!==typeof window?window:this,function(sb,Nb){"undefined"===typeof sb&&"object"===typeof window&&(sb=window);var N=function(b){if(b.FusionCharts&&b.FusionCharts.version)return b.FusionCharts;var z=b.document,G=b.navigator,v={window:b},F=v.modules={},E=v.interpreters={},t=Object.prototype.toString,
a=/msie/i.test(G.userAgent)&&!b.opera,Q=/loaded|complete/,r=!1,P=function(){var a=v.ready;v.ready=!0;v.raiseEvent&&(v.readyNotified=!0,v.raiseEvent("ready",{version:v.core.version,now:!a},v.core));v.readyNow=!a},T=function(a,b){var B,m;if(b instanceof Array)for(B=0;B<b.length;B+=1)"object"!==typeof b[B]?a[B]=b[B]:("object"!==typeof a[B]&&(a[B]=b[B]instanceof Array?[]:{}),T(a[B],b[B]));else for(B in b)"object"===typeof b[B]?(m=t.call(b[B]),"[object Object]"===m?("object"!==typeof a[B]&&(a[B]={}),T(a[B],
b[B])):"[object Array]"===m?(a[B]instanceof Array||(a[B]=[]),T(a[B],b[B])):a[B]=b[B]):a[B]=b[B];

How can I write a script to differentiate it from normal .js source code?

Any suggestion is appreciated.

EDIT -

Thank you for your response that this is minified code. I have a list of web apps produced by non-expert programmers. I am trying to programmatically identify the minified code located in the web applications' code bases. My goal is to run some analytics on the code. E.g. how similar the web apps are