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Filter an array of object, if X cannot find looking for Y

I have an array of object and I want to make a filter when a language does not exist use an another one. For example when I'm searching for the langauge de and it is not exist I want to search in this case to language en

const arrObj = [
  {id: 0, name: 'Zero', lang: 'hu', video: 'Clip'},
  {id: 1, name: 'One', lang: 'en', video: 'Clip'},
  {id: 2, name: 'Two', lang: 'en', video: 'Clip'},
  {id: 3, name: 'Three', lang: 'en', video: 'Trailer'},
  {id: 4, name: 'Four', lang: 'hu', video: 'Clip'},
  {id: 5, name: 'Five', lang: 'en', video: 'Trailer'},
  {id: 6, name: 'Six', lang: 'hu', video: 'Trailer'},
  {id: 7, name: 'Seven', lang: 'hu', video: 'Clip'},
]

const language = 'de'

const item = arrObj.filter(e => {
  if (e.lang === language && e.video === 'Trailer') {    
    return e.video === 'Trailer'
  } 
})

I've tried with find function and with different if else statement as well. I'm really stuck with this now. Any help would be appreciated

7 months ago · Juan Pablo Isaza

2 answers

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This will search using all given keywords until one of them returns some result. If no result is found, returns empty array;

let searchTerms = ["de", "be", "en"]

const arrObj = [{
        id: 0,
        name: 'Zero',
        lang: 'hu',
        video: 'Clip'
    },
    {
        id: 1,
        name: 'One',
        lang: 'en',
        video: 'Clip'
    },
    {
        id: 2,
        name: 'Two',
        lang: 'en',
        video: 'Clip'
    },
    {
        id: 3,
        name: 'Three',
        lang: 'en',
        video: 'Trailer'
    },
    {
        id: 4,
        name: 'Four',
        lang: 'hu',
        video: 'Clip'
    },
    {
        id: 5,
        name: 'Five',
        lang: 'en',
        video: 'Trailer'
    },
    {
        id: 6,
        name: 'Six',
        lang: 'hu',
        video: 'Trailer'
    },
    {
        id: 7,
        name: 'Seven',
        lang: 'hu',
        video: 'Clip'
    },
];


let search = (data, keywords) => {
    let filteredData = [];
    for (let j = 0; j < keywords.length; j++) {

        filteredData = data.filter(x => x.lang === keywords[j])
        if (filteredData.length != 0) {
            return filteredData;
        }

    }
    return filteredData;


}

console.log(search(arrObj, searchTerms))

7 months ago · Juan Pablo Isaza Report

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Accepted Answer · 2022-07-04T07:27:39.641Z

You can try using the logical or operator. Right side of the operator will only be evaluated when there is no trailer in de since find returns undefined (which is falsy) when there's no match:

const arrObj = [
  {id: 0, name: 'Zero', lang: 'hu', video: 'Clip'},
  {id: 1, name: 'One', lang: 'en', video: 'Clip'},
  {id: 2, name: 'Two', lang: 'en', video: 'Clip'},
  {id: 3, name: 'Three', lang: 'en', video: 'Trailer'},
  {id: 4, name: 'Four', lang: 'hu', video: 'Clip'},
  {id: 5, name: 'Five', lang: 'en', video: 'Trailer'},
  {id: 6, name: 'Six', lang: 'hu', video: 'Trailer'},
  {id: 7, name: 'Seven', lang: 'hu', video: 'Clip'},
]
const language = 'de';


const item = arrObj.find(e => e.video == 'Trailer' && e.lang === language)
                || arrObj.find(e => e.video == 'Trailer' && e.lang ===  'en');

console.log(item);