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Error handling: How can I await and re execute function after a timeout

I would like to handle async timeouts by awaiting the execution and re-executing a function including error handling after it fails.

Pseudo code:

01 call and await async function update()
02 if no error -> continue to line 05
03 sleep for 10000ms
04 Jump to line 01 //call update() again and handle possible errors
05 //continues execution

seems simple, but I cant get the asynchronous part working

Some common structure without any promise handling


let success = false;

while (!success) {
  try{
    update()
    success = true;
  } catch (e) {
    setTimeout(() => {},10000)
  }
}

I know that I should be working with .catch and promises, but cant figure out how.

Thanks for any help and explanations

7 months ago · Juan Pablo Isaza

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Accepted Answer · 2022-07-12T02:51:52.617Z

Not sure if this is what you're looking for, but here's an example of retrying an async call until success, with a 3 second delay between each attempt:

const wait = timeout => new Promise(resolve => setTimeout(resolve, timeout));

let counter = 0;

async function update() {
  console.log('Updating...');
  await wait(1000)
  if (counter === 3) {
    console.log('Update success');
  } else {
    counter += 1;
    throw new Error('Update failure');
  }
}

async function callUpdateUntilSuccess() {
  try {
    await update();
  }catch(err) {
    console.error(err);
    await wait(3000);
    return callUpdateUntilSuccess();
  }
}

(async () => {
  await callUpdateUntilSuccess();
})();