if for example i have an array that contains all messages sent or received to number 123456789
Messages: [
{ FromNumber: 9999, ToNumber: 123456789, Message: "first" },
{ FromNumber: 9999, ToNumber: 123456789, Message: "second" },
{ FromNumber: 123456789, ToNumber: 9999, Message: "me first2" },
{ FromNumber: 123456789, ToNumber: 9999, Message: "me second2" },
{ FromNumber: 123456789, ToNumber: 1234, Message: "me first" },
{ FromNumber: 1234, ToNumber: 123456789, Message: "second" },
],
And the result should look like
Messages: [
{ FromNumber: 123456789, ToNumber: 9999, Message: "me second2" },
{ FromNumber: 1234, ToNumber: 123456789, Message: "second" },
],
I tried something like this but that did not work, what would be the best solution?
Messages.filter(
(v, i, a) => a.findLastIndex((t) => t.ToNumber === v.FromNumber && t.FromNumber === v.ToNumber) === i
);
You could collect objects by their key, different from the common key and return the objects.
const
messages = [{ FromNumber: 9999, ToNumber: 123456789, Message: "first" }, { FromNumber: 9999, ToNumber: 123456789, Message: "second" }, { FromNumber: 123456789, ToNumber: 9999, Message: "me first2" }, { FromNumber: 123456789, ToNumber: 9999, Message: "me second2" }, { FromNumber: 123456789, ToNumber: 1234, Message: "me first" }, { FromNumber: 1234, ToNumber: 123456789, Message: "second" }],
common = 123456789,
result = Object.values(messages.reduce((r, o) => {
const key = o.FromNumber !== common ? o.FromNumber : o.ToNumber;
r[key] = o;
return r;
}, {}));
console.log(result);.as-console-wrapper { max-height: 100% !important; top: 0; }