Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

192
Views
How to detect focus on link elements and form input fields when activated with Tab key?

I want to detect when user focuses a link or input field by pressing the Tab key. Does anyone know of a way to do this? I have tried using the onFocus event, but it does not seem to work.

(I am not using jQuery, and I want to detect focus on links as well, so the similar question 16144611 is not the same as this one.)

about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

By combining keyUp and document.activeElement we can see if an element is currently focused.

We then need to look for the Tab key on keyup and you have a reasonable start at a solution.

const els = document.querySelectorAll('a, input');

window.addEventListener('keyup', function(e){
   // check the key code
   const code = (e.keyCode ? e.keyCode : e.which);
   if(code == 9 && els.length){
     checkFocus();
   }
   
});


function checkFocus(){
   // loop all elements (within our selector at the start) and see if they match the document.activeElement  
   for (const el of els) {
     if(document.activeElement == el){
       console.log("focused tag:" + el.tagName);
     }
   }
}
<button>Click me for focus, I am not checked</button>
<a href="#">Focused Link</a>
<label for="input1">I am also reported</label>
<input id="input1">
<button>Another button not announced</button>

Note that if you only ever want to check for links and inputs only a more efficient way to check would be:

const els = ['A', 'INPUT'];

window.addEventListener('keyup', function(e){
   // check the key code
   const code = (e.keyCode ? e.keyCode : e.which);
   if(code == 9 && els.length){
     checkFocus();
   }
   
});


function checkFocus(){
   // by checking the tagName we only have to do 2 loops no matter how many links or inputs there are on a page, which is far more efficient. The downside is it will check **every** link and input on the page. You would access the element with document.activeElelemnt instead if you need to know which item was focused.
   for (const el of els) {
     if(document.activeElement.tagName == el){
       console.log("focused tag:" + document.activeElement.tagName);
     }
   }
}
<button>Click me for focus, I am not checked</button>
<a href="#">Focused Link</a>
<label for="input1">I am also reported</label>
<input id="input1">
<button>Another button not announced</button>

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!