Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

320
Views
JavaScript Array forEach function not working?

I tried to do some changes in the W33 school's javascript code to learn about the difference between forEach and map, is there anyone can please tell me why the output of this code is still:

45,4,9,16,25

instead of

90,8,18,32,50

Isn't it forEach means call a function to every element in this array? I know I should not use return because the forEach does not return valid result.

const numbers = [45, 4, 9, 16, 25];

numbers.forEach(myFunction);
document.getElementById("demo").innerHTML = numbers;

function myFunction(value, index, array) {
  value * 2;
}
<!DOCTYPE html>
<html>

<body>

  <h2>JavaScript Array.forEach()</h2>
  <p>Calls a function once for each array element.</p>

  <p id="demo"></p>

</body>

</html>

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

The line value * 2 performs a calculation, but it doesn't do anything with the result of that calculation. You could change the line to value = value * 2 and that would assign the result of the calculation to the value variable. However, that still wouldn't change the values in the array, because the value variable is restricted to the scope of the function.

This is because when you transfer a number to another variable, you are only transferring the value, not the reference. i.e.

let a = 1;
let b = a;
a = 2; // a is 2, b is 1

This is different to arrays and objects, where the reference is transferred:

let a = [1];
let b = a;
a[0] = 2; // a[0] is 2, b[0] is 2

So a way to fix your code might be to manipulate the array instead, i.e.

const numbers = [45, 4, 9, 16, 25];
numbers.forEach(myFunction);

function myFunction(value, index, array) {
  array[index] = value * 2;
}

// numbers is [90,8,18,32,50]

This works. However, I would recommend the simplicity of map instead of forEach. Array#map uses the return value of each function call to replace each item in the array.

const numbers = [45, 4, 9, 16, 25];
const doubles = numbers.map(myFunction);

function myFunction(value, index, array) {
  return value * 2;
}

// numbers is [45,4,9,16,25]
// doubles is [90,8,18,32,50]
about 4 years ago · Juan Pablo Isaza Report

0

The function myFunction basically does nothing, it doubles the current value and does nothing with it. In your case, you need to mutate the array. But it's not a good idea to mutate the array which you're traversing.

To achieve your goal, I recommend creating a new array using the map function.

const numbers = [45, 4, 9, 16, 25];

const doubledNumbers = numbers.map((value) => val * 2); // [90, 8, 18, 32, 50]
document.getElementById("demo").innerHTML = doubledNumbers;
about 4 years ago · Juan Pablo Isaza Report

0

This is because you are not re-setting the value of numbers with the multiplied value.

You need to set it according to numbers[index] inside the map function.

const numbers = [45, 4, 9, 16, 25];

numbers.forEach(myFunction);
document.getElementById("demo").innerHTML = numbers;

function myFunction(value, index, array) {
  numbers[index] = value * 2;
}
about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!