Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

121
Views
django falta el token csrf en la función javascript .submit () (no ajax)

Estoy usando un javascript para enviar un formulario html a django. js se ve así:

 document.getElementById("fooform").submit();

y el formulario html se ve así:

 <form class="form-inline" id="fooform" action ="{% url 'foo:doo' %}" method="post"> {% csrf_token %} <input type="hidden" id="fooinput" value="" /> </form>

js puede escribir los datos en el campo de entrada sin ningún problema y también realizar el envío. mi problema es usar el token crsf. Ya puse el token {% csrf_token %} en todos los lugares imaginables. (Antes del formulario, antes del js...). en el código html el token también es correcto.

django me da el error:

 Reason given for failure: CSRF token missing or incorrect. In general, this can occur when there is a genuine Cross Site Request Forgery, or when Django's CSRF mechanism has not been used correctly. For POST forms, you need to ensure: Your browser is accepting cookies. The view function passes a request to the template's render method. In the template, there is a {% csrf_token %} template tag inside each POST form that targets an internal URL. If you are not using CsrfViewMiddleware, then you must use csrf_protect on any views that use the csrf_token template tag, as well as those that accept the POST data. The form has a valid CSRF token. After logging in in another browser tab or hitting the back button after a login, you may need to reload the page with the form, because the token is rotated after a login. You're seeing the help section of this page because you have DEBUG = True in your Django settings file. Change that to False, and only the initial error message will be displayed. You can customize this page using the CSRF_FAILURE_VIEW setting.

Editar: La vista.py:

 def foo_view(request): print(request.POST)

urls.py:

 app_name = 'foo' urlpatterns = \ [ path('doo', views.foo_view, name='foo_view'), ]
about 4 years ago · Juan Pablo Isaza
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!