Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

555
Views
Angular 7: TypeError: Cannot read properties of undefined (reading 'substr')

I have and angular 7.1.4 app that compiles successfully but when I open the console in my browser I see this error:

ERROR TypeError: Cannot read properties of undefined (reading 'substr')           core.js:14597 
at TruncatePipe.push../src/app/_services/truncate.ts.TruncatePipe.transform (truncate.ts:11:21)

If I understand this properly there is something wrong with the bellow code in my truncate.ts file. Here is my code:

import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
  name: 'truncate'
})
export class TruncatePipe implements PipeTransform {
  transform(value: string, limit = 25, completeWords = false, ellipsis = '...') {
    if (completeWords) {
      limit = value.substr(0, limit).lastIndexOf(' ');
    }
    return `${value.substr(0, limit)}${ellipsis}`;
  }
}

I am not sure what is wrong here? Any thoughts what could be wrong?

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

above all add one condition

if(value){
....your code
}
about 4 years ago · Juan Pablo Isaza Report

0

Indraraj26 is pointing out that you should wrap your code in a check-value before executing.

If value is ever null, you cannot take a substring of it, so in order to avoid this scenario, you should check if value != null or "". You can do that simply in Angular by using

import { Pipe, PipeTransform } from '@angular/core';

@Pipe({
  name: 'truncate'
})
export class TruncatePipe implements PipeTransform {
  transform(value: string, limit = 25, completeWords = false, ellipsis = '...') {
    if(value){
       if (completeWords) {
          limit = value.substr(0, limit).lastIndexOf(' ');
       }
       return `${value.substr(0, limit)}${ellipsis}`;
    }
  }
}

The if-statement will be false for null, and prevent your code from running and thus failing.

about 4 years ago · Juan Pablo Isaza Report

0

Before using value you should check if its undefined look at the following example:

function:


public validateText(text: string) {
  return text;
}

Calling this function now will cause error:

const text = 'just an example' as string | undefined; 

validateText(text);

error:

TS2322: Type 'string | undefined' is not assignable to type 'string'. Type 'undefined' is not assignable to type 'string'.

In your case you should check value before calling the function or inside it before substr or be more specific like so:

if (typeof value === 'string') {
//Your code 
}

// OR in short 

if (value) {
//Your code 
}

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!