I need to find first child element in array and just return it. Here is problem because here is few children elements and i need loop thought each and return every first children element.
Example of array:
let allItems =
[{ id: 1 ,
name: 'Test 1' ,
children: [
id: 12,
title: 'Child element'
]
},
{
id: 2 ,
name: 'Test 2'
},
{
id: 3 ,
name: 'Test 3',
children: [
id: 12,
title: 'Child element',
children: [
id: 123,
title: 'GRAND Child element',
]
]
}]
What's the problem here? Since there can be many children elements, do I need to find a parent for each of those elements?
After looping i need array to be:
[{ id: 1 ,
name: 'Test 1'
},
{
id: 2 ,
name: 'Test 2'
},
{
id: 3 ,
name: 'Test 3'
}]
Wihout children elements.
What I am try:
allItems.map(item => item).filter(filteredItem => !filteredItem.children);
But this is no return me good results
Based on your expected output, here is my solution.
Also note, that you had missing curly braces with your children.
See you modified snippet below:
let allItems = [{
id: 1,
name: 'Test 1',
children: [{
id: 12,
title: 'Child element'
}]
},
{
id: 2,
name: 'Test 2'
},
{
id: 3,
name: 'Test 3',
children: [{
id: 12,
title: 'Child element',
children: [{
id: 123,
title: 'GRAND Child element',
}]
}]
}
]
console.log(allItems.map(item => {
return {
id: item.id,
name: item.name
}
}))Using map and destructuring is a nice way to achieve what you're looking for
let allItems = [{
id: 1,
name: 'Test 1',
children: [{
id: 12,
title: 'Child element'
}]
},
{
id: 2,
name: 'Test 2'
},
{
id: 3,
name: 'Test 3',
children: [{
id: 12,
title: 'Child element',
children: [{
id: 123,
title: 'GRAND Child element',
}]
}]
}
];
const res = allItems.map(x => {
const {id, name} = x;
return {id, name};
});
console.log(res);Use these propertys for call first child:
.firstchild==>this property calls first Node
.firstElementChild==>calls first element