let array1= [ { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]}, { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]}, { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]} ]; const array2= ['2012'];resultado que queria
{ "id": 100, name: "A", "details": [{"year": "2012"}]}Sé que puedo filtrar la matriz con este código
array1.filter(o => o.details.some(p=> { return array2.includes(p.year) }) )Pero, ¿hay alguna manera de eliminar los objetos también?
Podemos reducir para evitar múltiples pasos
Esto reduce los filtros y elimina parte de la matriz de detalles.
let array1 = [ { "id": 100, name: "A", "details": [{"year": "2012"},{"data": "Test1"}]}, { "id": 101, name: "B", "details": [{"year": "2013"},{"data": "Test2"}]}, { "id": 102, name: "C", "details": [{"year": "2014"},{"data": "Test3"}]} ]; const array2 = ['2012']; let array3 = array1.reduce((acc, {id,name,details}) => { if (array2.includes(details[0].year)) { acc.push({ id, name, details: details[0] }) } return acc }, []) console.log(array3)