Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

152
Views
¿Cómo puedo eliminar elementos repetidos pero dejando el último elemento en la matriz? PHP

Bueno, necesito poder eliminar los elementos repetidos pero manteniendo el último elemento, es decir, eliminar los anteriores y dejar el último.

Esto es lo que tengo

 exists: [ 0: {intervention_id: 2, exists: "yes"} 1: {intervention_id: 2, exists: "no"} 2: {intervention_id: 2, exists: "yes"} 3: {intervention_id: 5, exists: "yes"} 4: {intervention_id: 6, exists: "no"} 5: {intervention_id: 12, exists: "yes"} ]

Tengo que borrar los anteriores.

 0: {intervention_id: 2, exists: "yes"} 1: {intervention_id: 2, exists: "no"}

y deja esto

 2: {intervention_id: 2, exists: "yes"}

Y esto es lo que necesito

 exists: [ 0: {intervention_id: 2, exists: "yes"} 1: {intervention_id: 5, exists: "yes"} 2: {intervention_id: 6, exists: "no"} 3: {intervention_id: 12, exists: "yes"} ]

Necesito mantener el último y eliminar los anteriores.

Intente esto pero elimine el último, no los anteriores.

 function unique_multidim_array($array, $key) { $temp_array = array(); $i = 0; $key_array = array(); foreach($array as $val) { if (!in_array($val[$key], $key_array)) { $key_array[$i] = $val[$key]; $temp_array[$i] = $val; } $i++; } return $temp_array; }
about 4 years ago · Juan Pablo Isaza
2 answers
Answer question

0

$data = [ [ 'intervention_id' => 2, 'exists' => 'yes' ], [ 'intervention_id' => 2, 'exists' => 'no' ], [ 'intervention_id' => 2, 'exists' => 'yes' ], [ 'intervention_id' => 5, 'exists' => 'yes' ], [ 'intervention_id' => 6, 'exists' => 'no' ], [ 'intervention_id' => 12, 'exists' => 'yes' ] ]; $map = array_column($data, 'exists', 'intervention_id'); array_walk($map, function (&$value, $key) { $value = [ 'intervention_id' => $key, 'exists' => $value ]; }, ARRAY_FILTER_USE_BOTH); $result = array_values($map); print_r($result);
about 4 years ago · Juan Pablo Isaza Report

0

Simplemente podría anular el valor del elemento actual usando la misma clave. En este caso, siempre obtendrá el último elemento para cada ID

 function unique_multidim_array($array, $key) { $uniq = []; foreach($array as $val) { $curVal = $val[$key]; // shortcut of the value $uniq[$curVal] = $val; // override previous value if exists } return array_values($uniq); // array_values to re-index array } $exists = [ ['intervention_id' => 2, 'exists' => 'yes'], ['intervention_id' => 2, 'exists' => 'no'], ['intervention_id' => 2, 'exists' => 'yes'], ['intervention_id' => 5, 'exists' => 'yes'], ['intervention_id' => 6, 'exists' => 'no'], ['intervention_id' => 12, 'exists' => 'yes'], ]; $uniq = unique_multidim_array($exists, 'intervention_id'); print_r($uniq);

Producción:

 Array( [0] => Array( [intervention_id] => 2 [exists] => yes ) [1] => Array( [intervention_id] => 5 [exists] => yes ) [2] => Array( [intervention_id] => 6 [exists] => no ) [3] => Array( [intervention_id] => 12 [exists] => yes ) )

demo en vivo

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!