I am trying to get the pattern from a string in JavaScript, where my string is 01-01-2000 - 01-01-2010 here I want to make these both date separate like date1 = 01-01-2000 and date2 = 01-01-2010.
I have tried this code :
var date = "01-01-2000 - 01-01-2010";
var date2 = date.match(/([0-9]{2})-([0-9]{2})-([0-9]{4})/);
console.log(date2[0]);
output: 01-01-2000 [correct]
but I using console.log(date2[1]) it displaying 01 only.
Please help how to achieve the goal make this function.
expecting output :
date[0]: 01-01-2000
date[1]: 01-01-2010
You Can use split instead If your date format is fixed.
var date = "01-01-2000 - 01-01-2010";
var date2 = date.split(" - ")
console.log(date2);if you want to work with pattern you only have to add the /g in the end for global search into the string:
var date = "01-01-2000 - 01-01-2010";
var date2 = date.match(/([0-9]{2})-([0-9]{2})-([0-9]{4})/g);
console.log(date2[0]);
console.log(date2[1]);You can give a try to String.matchAll() which returns an iterator of all results matching a string against a regular expression, including capturing groups.
Demo :
var date = "01-01-2000 - 01-01-2010";
var date2 = [ ...date.matchAll(/([0-9]{2})-([0-9]{2})-([0-9]{4})/g) ];
for (const match of date2) {
console.log(match[0])
}