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Temporizador de cuenta regresiva: oculta las variables a medida que caducan

buscando ayuda con un temporizador de cuenta regresiva, tengo que revelar un contenedor de la página en un momento específico. Me gustaría que los "días" "horas" "minutos" desaparezcan cuando lleguen a cero.

¿Alguien puede ayudar?

 <h3 id="demo"></h3> <script> // Set the date we're counting down to var countDownDate = new Date("1/21/2022 11:00:00").getTime(); // Update the count down every 1 second var x = setInterval(function() { // Get today's date and time var now = new Date().getTime(); // Find the distance between now and the count down date var distance = countDownDate - now; // Time calculations for days, hours, minutes and seconds var days = Math.floor(distance / (1000 * 60 * 60 * 24)); var hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60)); var minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60)); var seconds = Math.floor((distance % (1000 * 60)) / 1000); // Output the result in an element with id="demo" document.getElementById("demo").innerHTML = days + " day " + hours + " hours " + minutes + " min " + seconds + " sec "; // If the count down is over, write some text if (distance < 0) { clearInterval(x); document.getElementById("demo").innerHTML = "Reserve Tickets"; } }, 1000); </script>
about 4 years ago · Juan Pablo Isaza
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Actualizar variables solo si distancia > 0

 <h3 id="demo"></h3> <script> // Set the date we're counting down to var countDownDate = new Date("1/21/2022 11:00:00").getTime(); // Update the count down every 1 second var x = setInterval(function() { // Get today's date and time let now = new Date().getTime(); // Find the distance between now and the count down date let distance = countDownDate - now; // If the count down is over, write some text if (distance >= 0) { // Time calculations for days, hours, minutes and seconds let days = Math.floor(distance / (1000 * 60 * 60 * 24)); let hours = Math.floor((distance % (1000 * 60 * 60 * 24)) / (1000 * 60 * 60)); let minutes = Math.floor((distance % (1000 * 60 * 60)) / (1000 * 60)); let seconds = Math.floor((distance % (1000 * 60)) / 1000); // Output the result in an element with id="demo" document.getElementById("demo").innerHTML = days + " day " + hours + " hours " + minutes + " min " + seconds + " sec "; } else { clearInterval(x); document.getElementById("demo").innerHTML = "Reserve Tickets"; } }, 1000); </script>
about 4 years ago · Juan Pablo Isaza Report
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