I have a array of string and the patterns like #number-number anywhere inside a string.
Requirements:
If the # and single digit number before by hyphen then replace # and add 0. For example, #162-7878 => 162-7878, #12-4598866 => 12-4598866
If the # and two or more digit number before by hyphen then replace remove #. For example, #1-7878 => 01-7878.
If there is no # and single digit number before by hyphen then add 0. For example, 1-7878 => 01-7878.
I got stuck and how to do in JavaScript. Here is the code I used:
let arrstr=["#12-1676","#02-8989898","#676-98908098","12-232","02-898988","676-98098","2-898988", "380100 6-764","380100 #6-764","380100 #06-764"]
for(let st of arrstr)
console.log(st.replace(/#?(\d)?(\d-)/g ,replacer))
function replacer(match, p1, p2, offset, string){
let replaceSubString = p1 || "0";
replaceSubString += p2;
return replaceSubString;
}
Using the unary operator, here's a two liner replacer function.
const testValues = ["#162-7878", "#12-4598866", "#1-7878", "1-7878"];
const re = /#?(\d+?)-(\d+)/;
for(const str of testValues) {
console.log(str.replace(re, replacer));
}
function replacer(match, p1, p2) {
p1 = +p1 < 10 ? `0${p1}` : p1;
return `${p1}-${p2}`;
}I suggest matching # optionally at the start of string, and then capture one or more digits before - + a digit to later pad those digits with leading zeros and omit the leading # in the result:
st.replace(/#?\b(\d+)(?=-\d)/g, (_,$1) => $1.padStart(2,"0"))
See the JavaScript demo:
let arrstr=["#12-1676","#02-8989898","#676-98908098","12-232","02-898988","676-98098","2-898988", "380100 6-764","380100 #6-764","380100 #06-764"]
for(let st of arrstr)
console.log(st,'=>', st.replace(/#?\b(\d+)(?=-\d)/g, (_,$1) => $1.padStart(2,"0") ))The /#?\b(\d+)(?=-\d)/g regex matches all occurrences of
#? - an optional # char\b - word boundary(\d+) - Capturing group 1: one or more digits...(?=-\d) - that must be followed with a - and a digit (this is a positive lookahead that only checks if its pattern matches immediately to the right of the current location without actually consuming the matched text).let list_of_numbers =["#1-7878", "#162-7878", "#12-1676","#02-8989898","#676-98908098","12-232","02-898988","676-98098","2-898988"]
const solution = () => {
let result = ''
for (let number of list_of_numbers) {
let nums = number.split('-')
if (nums[0][0] == '#' && nums[0].length > 2) {
result = `${nums[0].slice(1, number.length-1)}-${nums[1]}`
console.log(result)
} else if (nums[0][0] == '#' && nums[0].length == 2) {
result = `${nums[0][0] = '0'}${nums[0][1]}-${nums[1]}`
console.log(result)
} else {
console.log(number)
}
}
}