I need Option value from this query "echo Option Value and JSArray".
this option value :
echo '<option value="'. $li['nama_emp'] .'">'. $li['nama_emp'].'</option>';
this Option Value JS :
$jsArray .= "prdName['" . $li['nama_emp'] . "'] = {akses:'" . addslashes($li['hak_akses']) . "'};\n";
thanks for help
<div class="form-group">
<label class="control-label col-sm-3">Asisten Manager/Manager</label>
<div class="col-sm-4">
<select name="mng" id="mng" class="form-control" onchange='changeValue(this.value)' required>
?php
$sql_don = "SELECT * FROM employee WHERE hak_akses in ('Manager','Asisten Manager')
and divisi='$divisi'AND active='Aktif' ORDER BY nama_emp ASC";
$ress_don = mysqli_query($conn, $sql_don);
$jsArray = "var prdName = new Array();\n";
while($li = mysqli_fetch_array($ress_don)) {
echo '<option value="'. $li['nama_emp'] .'">'. $li['nama_emp'].'</option>';
$jsArray .= "prdName['" . $li['nama_emp'] . "'] = {akses:'" . addslashes($li['hak_akses']) . "'};\n";
}
?>
</select>
</div>
</div>
<div class="form-group">
<label class="control-label col-sm-3">Jabatan </label>
<div class="col-sm-4">
<input class="form-control" name="akses" id="akses" readonly />
</div>
</div>
PHP snippet
$sql_don = "SELECT * FROM employee WHERE hak_akses in ('Manager','Asisten Manager') and divisi='$divisi'AND active='Aktif' ORDER BY nama_emp ASC";
$ress_don = mysqli_query($conn, $sql_don);
$result = mysqli_fetch_all($ress_don, MYSQLI_ASSOC);
Javascript snippet inside php file
let employee = <?= json_encode($result) ?>;
Now you have your query results as an array of objects which can be used in your javascript