Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

168
Views
Remove items from an array in order until matching item is found

I have an array of items

const test = [
  {
    id: '1',
  },
  {
    id: 'a',
  },
  {
    id: '3',
  },
  {
    id: 'b',
  },
  {
    id: '5',
  },
  {
    id: 'c',
  },
  {
    id: '7',
  },
];

These objects are always going to be in the same order. I'd like to be able to remove all items in order from the start until a specific id is reached.

I thought I could do this by just looping through until one is found and then pushing the items coming after that to a separate array:

let skippedArray = []

let skipUntilIndex = undefined

test.forEach((item, i) => {
  if(item.id === 'b') {
    skipUntilIndex = i
  }
  if(skipUntilIndex && i >= skipUntilIndex) {
    skippedArray.push(item)
  }
})

// [
//   {
//     id: 'b',
//   },
//   {
//     id: '5',
//   },
//   {
//     id: 'c',
//   },
//   {
//     id: '7',
//   },
// ]
console.log(skippedArray)

But this seems pretty dirty. Is there a better way to achieve this? I don't mind using lodash or similar libraries.

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

You can do it by using findIndex and slice methods, by findIndex you can find the index of target item in the array and with slice you can make a subArray of your original Array.

const data = [ { id: '1', }, { id: 'a', }, { id: '3', }, { id: 'b', }, { id: '5', }, { id: 'c', }, { id: '7', }, ];

const getSkippedItems = (id)=> {
    const index = data.findIndex(v => v.id == id);
    return index > -1 ? data.slice(index) : [];
}

const skippedArr = getSkippedItems('b');
console.log(skippedArr)

about 4 years ago · Juan Pablo Isaza Report

0

You can use Array.reduce() to filter out all items until our desired id is reached.

We'll only create the output array once we find the required id, then push remaining items into it.

const test = [ { id: '1' }, { id: 'a' }, { id: '3' }, { id: 'b' }, { id: '5' }, { id: 'c' }, { id: '7' } ];
 
const result = test.reduce((output, item) => { 
    if (!output && item.id === 'b') output = [];
    if (output) output.push(item);
    return output;
}, null);

console.log(result)
    
.as-console-wrapper { max-height: 100% !important; top: 0; }

about 4 years ago · Juan Pablo Isaza Report

0

You could take a closure over a flag and if found filter the rest by found.

const
    removeUntil = (id, found) => o => found ||= o.id === id,
    test = [{ id: '1' }, { id: 'a' }, { id: '3' }, { id: 'b' }, { id: '5' }, { id: 'c' }, { id: '7' }],
    result = test.filter(removeUntil('b'));

console.log(result);
.as-console-wrapper { max-height: 100% !important; top: 0; }

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!