Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

319
Views
What's the point of _curry1() in ramda.js?

I am reading right now the source code of Ramda and don't understand the point of _curry1().

function _curry1(fn) {
  return function f1(a) {
    if (arguments.length === 0 || _isPlaceholder(a)) {
      return f1;
    } else {
      return fn.apply(this, arguments);
    }
  };
}

Functions that are curried with this function can be called without arguments.

const inc = (n) => n + 1
const curriedInc = _curry1(inc)

// now it can be called like this
curriedInc(1)   // => 2
curriedInc()(1) // => 2

// but it works only with no arguments provided
const add = (a, b) => a + b
const curriedAdd = _curry1(add)

curriedAdd(1)     // => NaN
curriedAdd(1)(1)  // => TypeError: curriedAdd(...) is not a function
curriedAdd()      // => function f1(a)

Question: It seems to me that you can't chain arguments with this function at all. What are use cases for this function? How different is curriedInc()(1) from inc(1)?

about 4 years ago · Juan Pablo Isaza
1 answers
Answer question

0

_curry1, _curry2, and _curry3 are performance-boosting tricks that can't be used in the public curry function. Ramda (disclaimer: I'm an author) uses them to perform several tasks, clearly mostly doing the currying, but also checking for placeholders so that we can properly do some partial application. The other magic thing about Ramda's currying is the way that you can apply all, some, or even none of the required arguments, and so long as we're not complete, you get back another function looking for the remaining ones.

Obviously _curry1 theoretically shouldn't be necessary, but it makes it easier to add this sort of consistency:

const a = curry ((a, b, c) => ...)
a (1, 2, 3) == a (1, 2) (3) == a (1) (2, 3) == a (1) (2) (3) == a () () (1, 2) () (3)

Notice that last one. When you call a curried function still looking for arguments with no arguments at all, you get back the same function.

curry1 is what makes that happen; it adds consistency. But that's all it's for.

about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!