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¿Por qué el código javascript dado (log=>"ASDF") dentro del bloque asíncrono se ejecuta dos veces, mientras que la otra instrucción (log=>"asdf once") se ejecuta una vez?

La persona que llama es del reductor que estoy usando para que la aplicación envíe acciones para cambiar el estado de la aplicación.

el fn

 const AddFriendFirebase = async (name = "", current_uid) => { console.log("ASdf one"); const { uid } = await getUserFromName(name); console.log("ASdf"); createMessageDoc(current_uid, uid); }

Llamador

 case ADD_FRIEND: { AddFriendFirebase(payload, state.current_uid); return state; }

obtener UserFromName Fn

 const getUserFromName = async (name) => { console.log("get name fn"); const q = query(collection(db, "users"), where("user_name", "==", name)); const snapshot = await getDocs(q); if (!snapshot.docs[0]) { throw console.error("user not found!"); } const user = snapshot.docs[0].data(); return user; };
about 4 years ago · Juan Pablo Isaza
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