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JavaScript: matriz de grupos de objetos por propiedad en un objeto

si tengo una matriz js como la siguiente, ¿hay una forma sencilla de reagrupar los valores de la matriz por edad? Traté de reducirlo a una matriz, pero no ayudó. se reagrupa con la edad o el nombre

 let employees = [ { firstName:"Zion", lastName: "Rosy", age: 25, joinedDate:"January 24, 2020", }, { firstName: "Ana", lastName: "Rosy", age: 25, joinedDate: "January 15, 2019", }, { firstName: "Zion", lastName:"Albert", age: 30, joinedDate:"February 15, 2011", }, ];

Para reagrupar por edad así:

 let organizedByAge = { 25: [ { firstName:"Zion", lastName: "Rosy", age: 25, joinedDate:"January 24, 2020", }, { firstName: "Ana", lastName: "Rosy", age: 25, joinedDate: "January 15, 2019", }, ], 30: [ { firstName:"Zion", lastName:"Albert", age: 30, joinedDate:"February 15, 2011", }, ], };
about 4 years ago · Juan Pablo Isaza
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¿Existe una forma sencilla de reagrupar los valores de la matriz por edad?

Al reescribir arreglos y objetos, el enfoque más sencillo y legible suele ser usar un bucle for simple:

 for (let i = 0; i < employees.length; i++) { const age = employees[i]['age']; if (organizedByAge.hasOwnProperty(age)) { organizedByAge[age].push(employees[i]); } else { organizedByAge[age] = []; organizedByAge[age][0] = employees[i]; } }

Ejemplo de trabajo:

 let employees = [ { firstName:"Zion", lastName: "Rosy", age: 25, joinedDate:"January 24, 2020", }, { firstName: "Ana", lastName: "Rosy", age: 25, joinedDate: "January 15, 2019", }, { firstName: "Zion", lastName:"Albert", age: 30, joinedDate:"February 15, 2011", }, ]; let organizedByAge = {}; for (let i = 0; i < employees.length; i++) { const age = employees[i]['age']; if (organizedByAge.hasOwnProperty(age)) { organizedByAge[age].push(employees[i]); } else { organizedByAge[age] = []; organizedByAge[age][0] = employees[i]; } } console.log(organizedByAge);

about 4 years ago · Juan Pablo Isaza Report

0

Usando Array#reduce :

 const employees = [ { firstName:"Zion", lastName: "Rosy", age: 25, joinedDate:"January 24, 2020" }, { firstName: "Ana", lastName: "Rosy", age: 25, joinedDate: "January 15, 2019" }, { firstName: "Zion", lastName:"Albert", age: 30, joinedDate:"February 15, 2011" } ]; const organizedByAge = employees.reduce((map, e) => ({ ...map, [e.age]: [...(map[e.age] ?? []), e] }), {}); console.log(organizedByAge);

about 4 years ago · Juan Pablo Isaza Report

0

const groupByKey = (_data, _key) => { return _data.reduce((result, next) => { const key = next[_key]; result[key] = result[key]?.length ? [...result[key], next] : [next]; return result; }, {}); } console.warn(groupByKey(employees, 'age'));
about 4 years ago · Juan Pablo Isaza Report
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