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Simplemente si otra condición en JavaScript/es6

¿Cómo hago esto si es más simple?

 if (!request) { return 'no request'; } else { if (loading === '404') { return 'rejected'; } if (loading === '200' && !array1.length) { return 'fulfilled'; } }

si hay algún operador ternario, ¿cómo puedo hacerlo?

about 4 years ago · Juan Pablo Isaza
3 answers
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0

Podrías omitir otra parte, porque regresas si es true .

 if (!request) return 'no request'; if (loading === '404') return 'rejected'; if (loading === '200' && !array1.length) return 'fulfilled';
about 4 years ago · Juan Pablo Isaza Report

0

Puede usar la declaración if-elseif-else

 if(!request) return 'no request' else if(loading === '404') return 'rejected' else if(loading === '200' && !array.length) return 'fulfilled'
about 4 years ago · Juan Pablo Isaza Report

0

uno podría considerar...

 { // ... return ((!request && 'no request') || (loading === '404' && 'rejected') || (loading === '200' && !array1.length && 'fulfilled') || undefined // or 'failure' // or 'not fulfilled' ); }

... o ...

 { // ... let returnValue = (!request && 'no request') || (loading === '404' && 'rejected') || (loading === '200' && !array1.length && 'fulfilled') || undefined; // or 'failure'; // or 'not fulfilled'; // do more stuff ... // ... // ... maybe even change `returnValue` again. return returnValue; }
about 4 years ago · Juan Pablo Isaza Report
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