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0

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Simply if else condition in JavaScript/es6

How do I make this if else more simple.

if (!request) {
  return 'no request';
} else {
  if (loading === '404') {
    return 'rejected';
  }
  if (loading === '200' && !array1.length) {
    return 'fulfilled';
  }
}

if any ternary operator then how can I make it

about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

You could omit else part, because you return if true.

if (!request) return 'no request';
if (loading === '404') return 'rejected';
if (loading === '200' && !array1.length) return 'fulfilled';
about 4 years ago · Juan Pablo Isaza Report

0

You can use if-elseif-else statement

if(!request) return 'no request'
else if(loading === '404') return 'rejected'
else if(loading === '200' && !array.length) return 'fulfilled'
about 4 years ago · Juan Pablo Isaza Report

0

one might consider ...

{
  // ...
  return ((!request && 'no request')
    || (loading === '404' && 'rejected')
    || (loading === '200' && !array1.length && 'fulfilled')
    || undefined // or 'failure' // or 'not fulfilled'
  );
}

... or ...

{
  // ...
  let returnValue = (!request && 'no request')
    || (loading === '404' && 'rejected')
    || (loading === '200' && !array1.length && 'fulfilled')
    || undefined; // or 'failure'; // or 'not fulfilled';
  
  // do more stuff ...
  // ...
  // ... maybe even change `returnValue` again.
  
  return returnValue;      
}
about 4 years ago · Juan Pablo Isaza Report
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