Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

325
Views
React - How to pass props to a component passed as prop

I have a React component (React v15.5.4) that you can pass other components to:

class CustomForm extends React.Component {
  ...
  render() {
    return (
      <div>
          {this.props.component}
      </div>
    );
  }
}

And I have a different component that uses it:

class SomeContainer extends React.Component {
  ...
  render() {
    let someObjectVariable = {someProperty: 'someValue'};
    return (
      <CustomForm 
         component={<SomeInnerComponent someProp={'someInnerComponentOwnProp'}/>}
         object={someObjectVariable}
      />
    );
  }
}

Everything renders fine, but I want to pass someObjectVariable prop to the child component inside CustomForm (in this case that'll be SomeInnerComponent), since in the actual code you can pass several components to it instead of just one like the example.

Mind you, I also need to pass SomeInnerComponent its own props.

Is there a way to do that?

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

You can achieve that by using React.cloneElement.

Like this:

class CustomForm extends React.Component {
  ...
  render() {
    return (
      <div>
          {React.cloneElement(this.props.component,{ customProps: this.props.object })}
      </div>
    );
  }
}

Working Code:

class Parent extends React.Component{
  render() {
    return(
      <Child a={1} comp={<GChild/>} />
    )
  }
}

class Child extends React.Component{
  constructor(){
    super();
    this.state = {b: 1};
    this.updateB = this.updateB.bind(this);
  }
  
  updateB(){
    this.setState(prevState => ({b: prevState.b+1}))
  }
  
  render(){
    var Comp = this.props.comp;
    return (
      <div>
        {React.cloneElement(Comp, {b: this.state.b})}
        <button onClick={this.updateB}>Click to update b</button>
      </div>
    );
  }
}

const GChild = props => <div>{JSON.stringify(props)}</div>;
 
ReactDOM.render(
  <Parent />,
  document.getElementById('container')
);
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/react/15.1.0/react-dom.min.js"></script>

<div id='container' />

over 4 years ago · Santiago Trujillo Report

0

You can do in the same as you did for SomeInnerComponent.

Just pass named props.

Inside CustomForm,

render() {

  const MyComponent = this.props.component; //stored it in some variable

    return (
      <div> 
         <MyComponent customProps = {this.props.object} /> //access object here and passed it or passed individual props
      </div>
    );
  }

EDIT :

Please find the working demo here.

over 4 years ago · Santiago Trujillo Report

0

You have a couple of options to achieve what your asking.

class SomeContainer extends React.Component {
  ...
  render() {
   let someObjectVariable = {someProperty: 'someValue'};
    return (
      <CustomForm 
       component={<SomeInnerComponent propFromParent={someObjectVariable}/>}
       object={someObjectVariable}
      />
    );
  }

}

Or you can clone the component prop and apply the new props as Mayank said. In your case

class CustomForm extends React.Component {
  ...
  render() {
    return (
      <div>
        {React.cloneElement(this.props.component,
           {propFromParent:this.props.someObjectVariable})}
      </div>
  );
 }
}
over 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!