Please can anyone help me. I am able to sort an array into either ascending or descending order but I want to be able to sort the array above a numeric value.
For example if I have an array:
a0 = new Array(8, 1, 3, 9, 0, 0, 0, 0);
// Sort a0 to end up with;
// 1, 3, 8, 9, 0, 0, 0, 0;
I have included a fiddle: Basic template
I can only get it to work but with the zeros at the front of the sorted array
// 0, 0, 0, 0, 1, 3, 8, 9;
Thanks.
Just write a custom comparator function for the Array.prototype.sort function that ensures that 0 will be sorted last:
const a0 = new Array(8, 1, 3, 9, 0, 0, 0, 0);
a0.sort((a, b) => {
if (a === 0) return 1;
if (b === 0) return -1;
return a - b;
});
console.log(a0);You could sort zeros with a check of being not zero and move this values to bottom.
const array = [8, 1, 3, 9, 0, 0, 0, 0];
array.sort((a, b) => !a - !b || a - b);
console.log(...array);