Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

358
Views
Generating Random values for CSS (left and top) when refreshing / loading the page

I have several frames in my html that are draggable using a js function. They are scattered around with a unique "left" and "top" values in CSS.

I want to generate random left and top values every time the page is loaded / refreshed. They should range from 10 to 1000 (px).

div CSS (I have around 7 of them):

#mydiv1 {
    position: absolute;
    z-index: 0;
    width: 250px;
    height: 250px;
    top: 400px;
    left: 500px;
    background-color: black;
    border: 2px solid #e8ff26;
    text-align: center;
    box-shadow: 2px 2px 4px #888888;
    cursor: move;
}

Left and top are what I want to randomize for each of the 7 or more divs I have.

I looked up some JS examples but I have not been successful yet. Below is a not working attempt:

$(function(){
    var divClass = "div_"+Math.floor((Math.random() * 10) + 1);
    $('body').addClass(divClass);
});

attempt 2:

$(document).ready(function() {
    $("body").css("left", "(" + Math.floor(Math.random() * (10)) );
});
about 4 years ago · Juan Pablo Isaza
3 answers
Answer question

0

Random values can be generated and applied without using the JQuery

const myDiv = document.querySelector("#mydiv1");

const randomLeftValue = Number.parseInt(Math.random() * (1000 - 10) + 10);
const randomTopValue =  Number.parseInt(Math.random() * (1000 - 10) + 10);


myDiv.style.top = `${randomLeftValue}px`;
myDiv.style.left = `${randomTopValue}px`;
#mydiv1 {
    position: absolute;
    z-index: 0;
    width: 250px;
    height: 250px;

    background-color: black;
    border: 2px solid #e8ff26;
    text-align: center;
    box-shadow: 2px 2px 4px #888888;
    cursor: move;
}
<div id="mydiv1">

</div>

about 4 years ago · Juan Pablo Isaza Report

0

document.addEventListener("DOMContentLoaded", function(event) { 
    let item        = document.getElementById('mydiv1');
    let rng_top     = Math.floor(Math.random() * 1000);
    let rng_left    = Math.floor(Math.random() * 1000);
    item.style.top  = `${rng_top}px`;
    item.style.left = `${rng_left}px`;
});
about 4 years ago · Juan Pablo Isaza Report

0

$('document').ready(() => { // will only run once the page Document Object Model (DOM) is ready for JavaScript code to execute.

const left = Math.floor(Math.random() * 991 + 10); // random int [10 - 1000]

const top = Math.floor(Math.random() * 991 + 10); // random int [10 - 1000]

$('#mydiv1').css({ 'left': `${left}px`, 'top': `${top}px` }); // styling the div 

});
about 4 years ago · Juan Pablo Isaza Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!