So I have two arrays with the same length, but not entirely the same data as follows:
Array1: [{name: john, num: 030}, {name: david, num: 130}, {name: john, num: 200}, {name: jane, num: 500}]
Array2: [{name: john, num: 030}, {name: david, num: 130}, {name: jane, num: 500}, {name: '', num: ''}]
Array2 only has element where num matches Array1 num
Is there a way to make sure that these two arrays match their indexes even if the data does not match
for example, their index will look like this
Array1: [{name: john, num: 030}, {name: david, num: 130}, {name: john, num: 200}, {name: jane, num: 500}]
Array2: [{name: james, num: 030}, {name: frank, num: 130}, {name: '', num: ''}, {name: kate, num: 500},]
This means they match by index, and order is maintained. The main goal is that Array2 maintains the order of Array1.
According to the description seen in the question, list two logics
I implemented it according to the above logic, you can see if it helps you, if the logic does not meet your actual needs, you can provide more details and clear logic, I will adjust it
const array1 = [{name: 'john', num: '030'}, {name: 'david', num: '130'}, {name: 'john', num: '200'}, {name: 'jane', num: '500'}];
let array2 = [{name: 'david', num: '130'}, {name: 'jane', num: '500'}, {name: 'john', num: '030'}, {name: '', num: ''}];
const originalLength = array2.length;
const originalArr = array2.slice(0, originalLength);
array2.length = originalLength * 2;
const provide = (arr, field, index) => {
let result = arr.filter(a => a[field] == array1[index][field]);
if(result.length == 0){
result = arr.filter(a => a[field] == '');
}
return result[0];
};
for(let i=0; i<array1.length ; i++)
{
const item = provide(originalArr, 'num', i);
array2[i] = item;
}
array2.length = originalLength;
console.log(JSON.stringify(array2));