Business
Jobs
  • About Us
  • Solutions
    • Job Postings
      Post your job and receive qualified candidates in 48h.
    • Candidate Assessments
      500+ technical and psychological tests, plus anti-fraud.
    • Headhunting
      Tailor-made executive search from start to finish.
    • Payroll + EOR
      Payroll dispersal and EOR across 15+ LATAM countries.
  • Pricing
  • Jobs

0

337
Views
JS/ES6: Destructuring of undefined

I'm using some destructuring like this:

const { item } = content
console.log(item)

But how should I handle content === undefined - which will throw an error?

The 'old' way would look like this:

const item = content && content.item

So, if content is undefined -> item will also be undefined.

Can I do something similar using destructuring?

over 4 years ago · Santiago Trujillo
3 answers
Answer question

0

You can use short circuit evaluation to supply a default if content is a falsy value, usually undefined or null in this case.

const content = undefined
const { item } = content || {}
console.log(item)                       // undefined

A less idiomatic (see this comment) way is to spread the content into an object before destructuring it, because null and undefineds values are ignored.

const content = undefined
const { item } = { ...content }
console.log(item) // undefined

If you are destructuring function params you can supply a default (= {} in the example).

Note: The default value would only be applied if the destructured param is undefined, which means that destructuring null values will throw an error.

const getItem = ({ item } = {}) => item
console.log(getItem({ item: "thing" })) // "thing"
console.log(getItem())                  // undefined

try {
  getItem(null)
} catch(e) {
  console.log(e.message)                // Error - Cannot destructure property `item` of 'undefined' or 'null'.
}

Or even set a default value for the item property if the input object doesn't contain the property

const getItem = ({ item = "default" } = {}) => item
console.log(getItem({ item: "thing" })) // "thing"
console.log(getItem({ foo: "bar" }))    // "default"

over 4 years ago · Santiago Trujillo Report

0

const { item } = Object(content)
over 4 years ago · Santiago Trujillo Report

0

Destructuring the nested object is clean and short but sucks when source property is null or undefined in right side object

let say we have

const {
  loading,
  data: { getPosts },
} = useQuery(FETCH_POSTS_QUERY);

Solution 1 if we have data object but no getPosts then we can use:
(Setting default at each level)

const {
  loading,
  data: { getPosts = [] } = { getPosts: [] },
} = useQuery(FETCH_POSTS_QUERY);

Solution 2: if event data is undefined then:

const {
  loading,
  data: { getPosts } = { getPosts: [] },
} = useQuery(FETCH_POSTS_QUERY);
over 4 years ago · Santiago Trujillo Report
Answer question
Find remote jobs

Discover the new way to find a job!

Top jobs
Top job categories
Business
Post vacancy Pricing Sales
Legal
Terms and conditions Privacy policy
© 2026 PeakU Inc. All Rights Reserved.
Andres GPT
Show me some job opportunities
There's an error!